-22d^2-29d-9=0

Solution for -22d^2-29d-9=0 equation:

-22d^2-29d-9=0

a = -22; b = -29; c = -9;
Δ = b2-4ac
Δ = -292-4·(-22)·(-9)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-7}{2*-22}=\frac{22}{-44}
=-1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+7}{2*-22}=\frac{36}{-44}
=-9/11
$